In which of the following is the O-N-O bond a | vedclass

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(B) To determine the $O-N-O$ bond angle,we look at the hybridization and geometry of the molecules:$1$. $NO_2^+$: The nitrogen atom is $sp$-hybridized

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$NO_2^+$

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(B) To determine the $O-N-O$ bond angle,we look at the hybridization and geometry of the molecules:$1$. $NO_2^+$: The nitrogen atom is $sp$-hybridized with a linear geometry. The bond angle is $180^{\circ}$.$2$. $NO_2$: The nitrogen atom is $sp^2$-hybridized with one unpaired electron. The bond angle is approximately $134^{\circ}$.$3$. $NO_2^-$: The nitrogen atom is $sp^2$-hybridized with one lone pair. The bond angle is approximately $115^{\circ}$.$4$. $NO_3^-$: The nitrogen atom is $sp^2$-hybridized with no lone pairs,resulting in a trigonal planar geometry. The bond angle is $120^{\circ}$.Comparing these values,the $O-N-O$ bond angle is highest in $NO_2^+$.

List-$I$ (Compound)	List-$II$ (Shape/geometry)
$A$. $NH_3$	$I$. Trigonal Pyramidal
$B$. $BrF_5$	$IV$. Square Pyramidal
$C$. $XeF_4$	$II$. Square Planar
$D$. $SF_6$	$III$. Octahedral

In which of the following is the $O-N-O$ bond angle highest?

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The number of lone pairs of electrons on the central $I$ atom in $I_{3}^{-}$ is $.......$

Match List-$I$ with List-$II$.

List-$I$ (Compound) List-$II$ (Shape/geometry)

$A$. $NH_3$ $I$. Trigonal Pyramidal

$B$. $BrF_5$ $IV$. Square Pyramidal

$C$. $XeF_4$ $II$. Square Planar

$D$. $SF_6$ $III$. Octahedral

Choose the correct answer from the options given below:

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Which of the following is isostructural with $CO_2$?

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